(-n-18)/(n^2-12n+32)

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Solution for (-n-18)/(n^2-12n+32) equation: 


D( n )

n^2-(12*n)+32 = 0

n^2-(12*n)+32 = 0

n^2-(12*n)+32 = 0

n^2-12*n+32 = 0

n^2-12*n+32 = 0

DELTA = (-12)^2-(1*4*32)

DELTA = 16

DELTA > 0

n = (16^(1/2)+12)/(1*2) or n = (12-16^(1/2))/(1*2)

n = 8 or n = 4

n in (-oo:4) U (4:8) U (8:+oo)

(-n-18)/(n^2-(12*n)+32) = 0

(-n-18)/(n^2-12*n+32) = 0

n^2-12*n+32 = 0

n^2-12*n+32 = 0

DELTA = (-12)^2-(1*4*32)

DELTA = 16

DELTA > 0

n = (16^(1/2)+12)/(1*2) or n = (12-16^(1/2))/(1*2)

n = 8 or n = 4

(n-4)*(n-8) = 0

(-n-18)/((n-4)*(n-8)) = 0

-n-18 = 0 // + 18

-n = 18 // * -1

n = -18

n = -18

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